Question

What weight of carbon disulphide, $C S_{2}$ can be completely oxidised to sulphur dioxide and carbon dioxide by the oxygen liberated when $325 g$ of $Na _{2} O _{2}$ react with water? ($N a=23)$

Answer 1

Chemical equations :

$ CS _{2}+3 O _{2}  = CO _{2}+2 SO _{2} $

$ 2 Na _{2} O _{2}+2 H _{2} O  =4 NaOH + O _{2} $

$\because  CS _{2} \equiv 3 O _{2} ; \text { and } 2 Na _{2} O _{2} \equiv O _{2} $

$\text { Hence }  6 Na _{2} O _{2} \equiv 3 O _{2} $

$\therefore \quad CS _{2}  \equiv 3 O _{2}  \equiv 6 Na _{2} O _{2} $

$ 12+64 $       $ 6(23 \times 2+16 \times 2) $

$ =76 \equiv 468 $

$ \because 468 g Na _{2} O _{2} \equiv 76 g CS _{2}$

$\therefore \quad 325 g Na _{2} O _{2} \equiv \frac{76 \times 325}{468} g CS _{2}= 5 2 \cdot 7 g CS _{2} \text {. }$