Assuming 100% yield of the reaction, how many moles of NaHCO3 will produce 448 mL of CO2 gas at STP according to the reaction —

Question

Assuming 100% yield of the reaction, how many moles of NaHCO3 will produce 448 mL of CO₂ gas at STP according to the reaction —

NaHCO₃ (On Heating) → Na₂CO₃ + CO₂ + H₂O (Unbalanced)

(A) 0.04

(B) 0.4

(C) 4

(D) 40

Answer 1

ANSWER : 0.04 moles of NaHCO3 will produce 448 mL of CO₂ gas at STP according to the above reaction.

So, The correct option of this question is (A).

SOLUTION —