Question

$2 KI + I _{2}+22 HNO _{3} \rightarrow 2 HIO _{3}+2 KIO _{3}+22 NO _{2}+10 H _{2} O$

If 3 mole of $KI \& 2$ moles $I _{2}$ are reacted with excess of $HNO _{3}$. Volume of $NO _{2}$ gas evolved at NTP is

(A) $739.2 Lt$

(B) $1075.2 Lt$

(C) $44.8 Lt$

(D) $67.2$ Lt

Answer 1

If 3 mole of KI & 2 moles I₂ are reacted with excess of HNO₃. Than, Volume of NO₂ gas evolved at NTP is 739.2 Lt.

So, The correct option of this question is (A).