What approximate volume of 0.40 M Ba(OH)2 solution must be added to 50.0 mL of 0.30 M NaOH solution to get a solution in which the molarity of the OH− ions is 0.50 M?
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What approximate volume of 0.40 M $Ba ( OH )_{2}$ solution must be added to $50.0 mL$ of 0.30 M $NaOH$ solution to get a solution in which the molarity of the $OH ^{-}$ions is $0.50 M$ ?

(A) $33 mL$

(B) $66 mL$

(C) $133 mL$

(D) $100 mL$

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33 mL of 0.40 M Ba(OH)2 solution must be added to 50.0mL of 0.30 M NaOH solution to get a solution in which the molarity of the OH ions is 0.50M.

So, The correct option of this question is (A).

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