The virial equation for 1 mole of a real gas is written as :
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The virial equation for 1 mole of a real gas is written as :

$P V=R T\left[1+\frac{A}{V}+\frac{B}{V^{2}}+\frac{C}{V^{3}}+\ldots . \text { to higher power of } n\right]$

Where $A, B$ and $C$ are known as virial cofficients. If Vander waal's equation is written in virial form, then what will be the value of $B$ :

(A) $a-\frac{b}{R T}$

(B) $b^{3}$

(C) $b-\frac{a}{R T}$

(D) $b^{2}$

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If Vander Waal's equation is written in virial form, then the value of B will be b2So, The correct option of this question is (D).

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