Question

समाकलन करें : $\int \sin ^3 x d x$

Answer 1

$\begin{aligned}

$\therefore \quad I & =\int \sin ^2 x \cdot \sin x d x\\$

$=\int\left(1-\cos ^2 x\right) \cdot \sin x d x \\$

& =\int\left(1-z^2\right) \cdot x-d z=-\int d z+\int z^2 d z \\
$
& =-z+\frac{z^3}{3}+c=-\cos x+\frac{\cos ^3 x}{3}+c

\end{aligned}

$