हल : बाँया पक्ष —
$=\sin ^{-1} \frac{3}{5}-\cos ^{-1} \frac{12}{13}=\sin ^{-1} \frac{3}{5}-\sin ^{-1} \frac{5}{13}$
$
=\sin ^{-1}\left(\frac{3}{5} \sqrt{1-\left(\frac{5}{13}\right)^2}-\frac{5}{13} \sqrt{1-\left(\frac{3}{5}\right)^2}\right) \\
=\sin ^{-1}\left(\frac{3}{5} \times \frac{12}{13}-\frac{5}{13} \times \frac{4}{5}\right)=\sin ^{-1}\left(\frac{16}{65}\right)
$
