Question

5 g of $ K _{2} SO _{4}$ was dissolved in water to prepare $250 mL$ of solution. What volume of this solution should be used so that $2.33 g$ of $BaSO _{4}$ may be precipitated from $BaCl _{2}$ solution.

$K _{2} SO _{4}+ BaCl _{2} \longrightarrow BaSO _{4}+2 KCl$

(A) $87 mL$

(B) $174 mL$

(C) $8.7 mL$

(D) $17.4 mL$

Answer 1

87 mL of this solution should be used so that 2.33g of BaSO₄ may be precipitated from BaCl₂ solution.

So, The correct option of this question is (A).