Solution
Let the amounts of milk and water are $8 x$ and $7 x$.
$
\begin{array}{l}
\therefore \quad \frac{8 x}{7 x+11}=\frac{8}{9} \\
\Rightarrow \quad 72 x=56 x+88 \\
\Rightarrow \quad 72 x-56 x=88 \\
\Rightarrow \quad 16 x=88 \\
\therefore \quad x=\frac{88}{16}
\end{array}
$
$\therefore$ The amount of milk $=8 x$
$=8 \times \frac{88}{16}$
$=$ 44 Litres; Ans.
Correct option $=(D)$
Trick :
Milk: Water
$
\begin{aligned}
8: & 7 \\
8: & 9 \\
\hline & 2=11
\end{aligned}
$
$\therefore$ Amount of milk $=\frac{11}{2} \times 8$
$=44$ litres: Ans