Let the numiver of girls in the class $=y$
$\therefore \quad$ Number of boys in the class $=100-y$
Now, $\bar{x}_1=25, n_1=y, \bar{x}_2=50, n_2=100-y$
and
$\begin{array}{llrl}\therefore 35=\frac{25 \times y+50 \times(100-y)}{100} \\\Rightarrow 3500=25 y+5000-50 y \\\Rightarrow 25 y=1500 \\\Rightarrow y =60\end{array}$
$\therefore$ Number of girls in the class $=60$
So, The correct option of this question will be (C).