SOLUTION —
Let $\frac{2 z_1}{3 z_2}=t y \Rightarrow \frac{z_1}{z_2}=\frac{3}{2} i y$
$\therefore \quad\left|\frac{z_1-z_2}{z_1+z_2}\right|=\frac{\mid \frac{z_1}{z_2}-1}{\mid \frac{z_1}{z_2}+1}\left|=\frac{\mid \frac{3}{2} i y-1}{\mid \frac{3}{2} i y+1}\right|=1 \quad(\because|z|=\mid \bar{z}) \mid$
So, The correct option will be (B).