SOLUTION —
$\therefore \operatorname{amp}(z)=\tan ^{-1}\left(\frac{1-\cos \alpha}{\sin \alpha}\right)$
$=\tan ^{-1}\left(\frac{2 \sin ^2 \frac{\alpha}{2}}{2 \sin \frac{\alpha}{2} \cos \frac{\alpha}{2}}\right)$
$=\tan ^{-1} \tan \left(\frac{\alpha}{2}\right)=\frac{\alpha}{2}$
So, The correct option will be (B).